a,b,c can do a piece of work in 12,24,8 days .three of them started the work together and after a day c left the work the find the days in which a and b finish the remaining work?
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A: 12 days ⇒ 1 work
1 day ⇒1/12 work
B: 24 days ⇒ 1 work
1 day ⇒ 1/24 work
C: 8 days ⇒ 1 work
1 day ⇒ 1/8 work
(using simple unitary method)
work done in 1 day by A,B and C together,
⇒1/12+1/24+1/8=1/4 work
so work remaining after C left:
1-1/4=3/4
now, work done by A and B in 1 day,
1/12+1/24=1/8
using Unitary method,
1/8 work ⇒ 1day
1 work ⇒ 8 days
3/4 work ⇒ 8*3/4 =6 days
hope that helps :)
1 day ⇒1/12 work
B: 24 days ⇒ 1 work
1 day ⇒ 1/24 work
C: 8 days ⇒ 1 work
1 day ⇒ 1/8 work
(using simple unitary method)
work done in 1 day by A,B and C together,
⇒1/12+1/24+1/8=1/4 work
so work remaining after C left:
1-1/4=3/4
now, work done by A and B in 1 day,
1/12+1/24=1/8
using Unitary method,
1/8 work ⇒ 1day
1 work ⇒ 8 days
3/4 work ⇒ 8*3/4 =6 days
hope that helps :)
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