Math, asked by learner9892, 7 hours ago

. A, B, C, D and E play a game in which each one is either a dog or a mouse.

A dog’s statement is always false while a mouse’s statement is always true.

A says that B is a mouse. C says that D is a dog.

E says that A is not a dog. B says that C is not a mouse.

D says that E and A are different kinds of animals. How many play dogs ?

answer plz:​

Answers

Answered by Frank7652
2

Answer:

only one dog plays i.e D

Step-by-step explanation:

from given statements

A is not a dog

B is a mouse

C is not a mouse

D is a dog

E and A are different kind of animals

so:- only (1)one dog plays

Answered by Anonymous
0

Given:  A, B, C, D and E play a game in which each one is either a dog or a mouse. A dog’s statement is always false while a mouse’s statement is always true. A says that B is a mouse. C says that D is a dog. E says that A is not a dog. B says that C is not a mouse. D says that E and A are different kinds of animals.

To find: How many play dogs

Solution:

A is not a dog, since a dog’s statement is always false

B is a mouse since a mouse’s statement is always true.

C is not a mouse, since it says that D is a dog

D is a dog

E and A are different kinds of animals

only one dog plays which is D.

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