(a-b-c-d)-(d-a-b+2c)
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Please
Step-by-step explanation:
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this is your answer
I can't understand your question but I think you ask this question.
Step-by-step explanation:
If a,b,c,d are in a G.P. , ...
If a,b,c,d are in a G.P., then show that (a−d) 2 =(b−c) 2 +(c−a) 2+(d−b) 2
ANSWER
R.H.S=(b−c) 2+(c−a) 2+(d−b) 2
Being a,b,c and d in GP,
ba= cc= dd ,b 2=ac,c
2=bd and ac=bd, ad=bc,
RHS=b 2+c 2−2bc+c 2+a 2 −2ac+d 2+b 2−2bd=2b
2 −2bc+2c 2+a 2 −2b 2+d 2−2c =a
2+d2−2ad=(a−d) 2 =LHS
Hope it is helpful for you
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