Question

A+B+C+D+E=30 Find A, B, C, D and E such that all numbers belong to (1, 3, 5, 7, 9, 11, 13, 15) and any number can be repeated as much times as you want

Answer 1

11+9+7+3=30//
13+5+5+7=30//
15+5+3+7=30//
9+9+9+3=30//
7+7+7+9=30//
15+5+5+5=30//
11+1+5+13=30//

Answer 2

• Odd numbers don't add up to give you an even number. It is possible only in case of factorial.

3!+1+3+13+7=30  

3!+3!+3!+3!+3!=30

11+1+3+15=30

3! + 15 + 9 = 30