Question

A B C D E + A B C D E + A B C D E = D E O A B C Find the digits representated by the letters....pls helppppp

Answer 1

12345 + 12345+12345= 4515123 I think this one is the answer

Answer 2

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$\color{violet}\huge\bold\star\underline\mathcal{Here\:Is\:Ur\:AnSweR}\star$

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» ABCDE + ABCDE + ABCDE = DEOABC

» 3(ABCDE) = DEOABC

» since, the ABCDE are 5 digits

let's replace it as

» 3(5)ABCDE = DEOABC

» 15 ABCDE = DEOABC

“O” is 15th enligh alphabet.
Hence,

» OABCDE = DEOABC

in product, we can write a×b×c as c×b×a also.

so,

» OABCDE = DEOABC

» DEOABC = DEOABC

$\marquee{Hence\:Proved}\marquee$

the digits are

» ABCDE + ABCDE + ABCDE = DEOABC

»12345 + 12345 + 12345 = 45(15)123

» 3(12345) = (3×5)12345

»$\fraction{3}/{3}$ (12345) = 5(12345)

» 1(12345) = 5(12345)

» so,the number is 455123

__________
or
__________

the simple anSweR is

» 45(15)123
» 4515123

as,
A » 1
B » 2
C » 3
D » 4
E » 5
O » 15



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