←----A------B-----C-----D--→
Points A-B-C-D are collinear as shown in the figure. If I(AD) = 12,
1(AC) = 7 and 1(BD) = 9.
Find:
(i) l(AB), (ii) l(CD), (iii) I(BC)
Answers
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Answer:
AD=12
AC+BD=9+7=16
Since, in AC+BD, we use BC one extra time
=> AC+BD-BC=AD
or,16-BC=12
or,BC=16-12=4
i) AB= AC-BC= 7-4=3
ii) CD= BD-BC=9-4= 5
iii) BC=4
Explanation:
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