Math, asked by priyankajangid9374, 11 months ago

A,b,c have to supply an order of 100 pens a,b,c make a pen in 2,3,4 hr respectively in how many days they will complete the work if each one make a complete pen himself without the help of other

Answers

Answered by ashwanisingh2001
12

In 1 hour

A makes 1/2 pen

B makes 1/3 pen

C makes 1/4 pen

in x hours, A makes x/2, B makes x/3 and C makes x/4 pens

In x hours, 13x/12 pens are made, x((1/2)+(1/3)+(1/4))

if 13x/12=100

13x=1200

x=92.3 pens.

There can't be fractional pens, so look at 92 hours first

A will make 46 pens completely and no more

B will make 30 pens and is part way through the 31st.

C will make 23 pens completely and no more

That is 99 pens.

In the 93rd hour, A will make another half pen and C another 1/4 pen, but B will finish the 31st pen, and there will be 100 pens.

93 hours is 3 days and 21 hours. or 3 7/8 days.

Please mark this answer as brainliest.

Answered by xXMarziyaXx
2

In 1 hour

A makes 1/2 pen

B makes 1/3 pen

C makes 1/4 pen

in x hours, A makes x/2, B makes x/3 and C makes x/4 pens

In x hours, 13x/12 pens are made, x((1/2)+(1/3)+(1/4))

if 13x/12=100

13x=1200

x=92.3 pens.

There can't be fractional pens, so look at 92 hours first

A will make 46 pens completely and no more

B will make 30 pens and is part way through the 31st.

C will make 23 pens completely and no more

That is 99 pens.

In the 93rd hour, A will make another half pen and C another 1/4 pen, but B will finish the 31st pen, and there will be 100 pens.

93 hours is 3 days and 21 hours. or 3 7/8 days.

Please mark this answer as brainliest.

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