Question

a, b,c in g.p. of common ratio r . if a 2b 3c in Ap then r is?​

Answer 1

Answer:

Step-by-step explanation:

Since, a,b & c are in GP with common ratio r.

Therefore, b = ar & c = a(r^2) ….(1)

Also, a, 2b & 3c are in AP.

So, we have, 2×2b = a+3c

=> 4b = a+3c

=> 4ar = a+3a(r^2) [using (1)]

=> 4r = 1+3(r^2) [as, a ≠ 0]

=> 3(r^2) -4r +1 = 0

=> (r-1)(3r-1) = 0

=> r = 1/3, as r ∈ (0,1).

Hope, it'll help..!!

Answer 2

Answer:

Solution is in the pic.

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