Question

on tossing three coins at a time find
(1) All possible outcomes
2) probability of three heads
3) at most two heads​

Answer 1

Step-by-step explanation:

(1) All favorable outcomes n(S) = 8

that is ,

HHH, HHT, HTH, THH, HTT, THT, TTH, TTT

Ans. 8

(2) Probability of three heads

n(A) = 1

P(A) = n(A)/ n(S) =1/8

Ans. 1/8

(3) At most two heads n(B) = 4

P(B) = n(B)/n(S) =4/8 = 1/2

Ans. 1/2

Hope you're satisfied with my Answer

Answer 2

Step-by-step explanation:

S={HHH, TTT, HHT, TTH, HTH, THT, THH, HTT}

n(S) =8

Let A be the event to get three heads

A={HHH}

n(A) =1

P(A)=1/8

Let B be the event to get at most two heads

B={HHT, HTH, THH}

n(B) =3

P(B) =3/8