Question

a + b + c is equals to zero then a square + b square + c square divided by b square minus C A is equals to how much​

Answer 1

Answer:

-2ac/a^2-c^2-3ac is your question's answer

Answer 2

To solve this problem, we can start by using the fact that a + b + c = 0, which means that c = -a - b. We can substitute this expression for c into the numerator of the expression we want to simplify:

b² + c² + a² = b² + (-a - b)² + a²

= b² + a² + 2ab + b² + a²

= 2(a² + b² + ab)

Next, we can simplify the denominator using the same expression for c:

b² - ca = b² - b(-a - b) = b² + ab

Now, we can substitute these expressions into the original expression:

(b² + c² + a²) / (b² - ca) = [2(a² + b² + ab)] / (b² + ab)

The factor of (a² + b² + ab) cancels out, leaving:

(b² + c² + a²) / (b² - ca) = 2

Therefore, if a + b + c = 0, then (b² + c² + a²) / (b² - ca) simplifies to 2.