Question

A+B+C = pi/2 thnen find value of tanAtanB+tanBtanC+tanCtanA

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

Answer:

tan(A+B+C)= s1-s3/1-s2

=tanA + tan B + tan c -tanAtanBtan ______________________________ 1-( tanA tan B + tanB tanC+ tanCtanA )

0 = 1-s2

s2= 1

tanAtanB + tanBtanC + tanCtanA=1

Explanation

s2 = submission of 2 terms

tan(A + B +C )=tan π/2=. 1/0