Question

A,b,c together can piece a in 7 days.a and b take 5 days more to complete the same work than that of a and

c.b and c together can complete work in 16 days. in how many days c alone to complete the work?

Answer 1

(A+B+C)7=WORK ————equation 1

(B+C)16 =WORK ————-equation 2

EQUVATE 1 & 2

(A+B+C)7 = (B+C)16

(A) 7 = (B+C) 9

A/(B+C) = (9/7)

Efficiency A=9 , B+C =7 put in equation 1

WORK = (9+7)7

work = 16*7 = 112

condition given (A+B) (X+5) = (A+C) X

(A+B)/(A+C) = X/(X+5) ——— equation 3

apply value of A =9 We know that (B+C) = 7

Let take B=1 C=6

(9+1)/(9+6) = x/(x+5)

10/15 = x/(x+5) condition satisfied so C=6

C = WORK/EFFICIENCY

C = 112/6

C = 18 2/3 DAYS