Question

(a-b-c)whole cube = ?​

Answer 1

Answer:

sorry I cannot find the right answer for this question

Answer 2

$\huge \color{red} \boxed{ \text \color{cyan} \fbox \color{green}{its \: tanya}}$

$\huge \color{pink} \bigstar{answer}$

{ a - b - c}^3

{ a - b - c}^3={ a -( b+ c)}^3

{ a - b - c}^3={ a -( b+ c)}^3= a^3 + (b+c)^3- 3a(b+c){ a-b-c}

{ a - b - c}^3={ a -( b+ c)}^3= a^3 + (b+c)^3- 3a(b+c){ a-b-c}= a^3+b^3+c^3+ 3bc(b+c)-3a[ ab-b^2-bc+ac-bc-c^2]

{ a - b - c}^3={ a -( b+ c)}^3= a^3 + (b+c)^3- 3a(b+c){ a-b-c}= a^3+b^3+c^3+ 3bc(b+c)-3a[ ab-b^2-bc+ac-bc-c^2]= a^3+b^3+c^3 + 3[ b^2c+bc^2-a^2b+ab^2-a^2c+abc+ac^2 ].....