Question

A+b+c whole cube is equals to 3abc if a+b+c=0 proof

Answer 1

Heya User,

--> ( a + b + c ) = 0  { given }
=> [ -a ] = b + c
=> ( -a )³ = ( b + c )³
=> - a³ = b³ + c³ + 3bc ( b + c )
=> - a³ = b³ + c³ + 3bc ( -a )  --> { b + c = -a } 
=> -a³ = b³ + c³ - 3abc
=>  a³ + b³ + c³ = 3abc  ^_^ Proved .. :p

Eh! I lately saw that you've asked for the following proof :->
---> ( a + b + c )³ = 3abc { which is however soooo wrong =_= }

And hey ! If uh asked for a different one =_= ,
---> find the proof above