Question

A+ B can compelete a work 40% lesser then c while b+c can compelete the work in 60% lesser time than A if they together can complete work in 20 days then how many day will a alone compelete same work ?​

Answer 1

Answer:

Let time taken by C

=

x

and time taken by B+A

=

0.6

x

1

x

+

1

0.6

x

=

1

20

⇒

x

=

160

3

days. (C alone can)

Let the time taken by A

=

x

and time taken by B+C

=

0.4

x

1

x

+

1

0.4

x

=

1

20

x

=

70

days. (A alone can)

Step-by-step explanation:

give me mare and more

Answer 2

Answer:

a+ b

a+ b b+ c

a+ b b+ c first see this

Step-by-step explanation:

NOW A + B IS 40% LESSER AND B + C CAN COMPLETE WORK IN 60% LEISURE TIME 20 DAYS WE HAVE TO COMPLETE WORK 40 + 60 PLUS 20 DAYS

40

60

+ 20 DAYS

120 ANS