a+b equal to 10 and ab equal 21 find the value a cube b cube
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Answer:
Given that : -
(a + b) = 10 and ab = 21.
a {}^{3} + b {}^{3} = ? \:
Now,
(a + b) = 10
=> (a + b)² = (10)² [squaring both sides .]
=> a² + b² + 2ab = 100
=> a² + b² = 100 - (2 × 21)
=> a² + b² = 100 - 42
=> a² + b² = 58
Now,
---------
a³ + b³
= (a + b)(a² - ab + b²)
Putting the values ,we get,
= 10 × [(a² + b²) - ab]
= 10 × (58 - 21)
= 10 × 37
= 370
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