A+B=pie/4 prove that (1+tanA)(1+tanB)
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Just take tan on both sides and use formula tan(A+B)
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A+B = π /4 =45°
TAKE TAN TO BOTH SIDES
Tan(A+B )= Tan45°
tanA+tanB/1-tanAtanB =1
1-tanAtanB=tanA+tanB
1= tanA + tanB + tanA.tanB
1+1=1+tanA+tanB+tan.AtanB
2=(1+tanA)(1+tanB)
TAKE TAN TO BOTH SIDES
Tan(A+B )= Tan45°
tanA+tanB/1-tanAtanB =1
1-tanAtanB=tanA+tanB
1= tanA + tanB + tanA.tanB
1+1=1+tanA+tanB+tan.AtanB
2=(1+tanA)(1+tanB)
adityakjha24:
hope this will help... if any query feel free to ask
Please explain from last 2 line
ok
add 1 to both side.. this will not create any difference in equation...after that take common
1(1+tanA) + tanB (1+ tanA) = (1+tanA)(1+tanB)
Oh I got it thanks
always wlcm...foloow me for any kinda help in maths
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