Math, asked by rachnaagarwal681, 10 months ago

a b
Three numbers a b and c are in the ratio 3:4:5
If a3 + b3 + c³ - 3 ² = 4069, find the values of a b
and c.​

Answers

Answered by hasish4099
1

Answer:

let ,

a=3x, b=4x, c=5x

(3x)³+(4x)³+(5x)³-3² = 4069

27x³+64x³+125x³-9 = 4069

216x³-9 = 4069

x³=4069/216+9

x³=27(approx)

x=3

a=3×3=9

b=4×3=12

c=5×3=15

Answered by purabpatel2312
2

Answer:

Step-by-step explanation:

Let a b c be 3x,4x,5x so a=3x b=4x c=5x

3x^3+4x^3+5x^3-3^2= 4069

27x^3+ 64x^3 + 125x^3 -9 = 4069

216x^3 -9 = 4069

x^3 = 4069/216 +9

x^3 = 27

x = 3

a = 3x, 3 x 3 = 9

b = 4x, 4 x 3 = 12

c = 5x, 5 x 3 = 15

So a=9 b=12 c=15

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