(a+b)whole cube - (a-b)whole cube
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Answer:
2b³ + 6a²b
Step-by-step explanation:
FORMULA USED:
(a+b)³ = a³ + b³ + 3a²b + 3ab²
(a-b)³ = a³ - b³ - 3a²b + 3ab²
(a+b)³ - (a-b)³ = a³ + b³ + 3a²b + 3ab² - [a³ - b³ - 3a²b + 3ab²]
= a³ + b³ + 3a²b + 3ab² - a³ + b³ + 3a²b - 3ab²
= 2b³+6a²b
remaining all will be subtracted and gets cancelled.
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