Question

(a+b)whole cube+(b+c)whole cube+(c+a)whole cube-3(a+b)(b+c)(c+a) factorise the polynomial please give me ans​

Answer 1

Answer:

here is your answer :)

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Answer 2

Ans:- (a+b)³+(b+c)³+(c+a)³ - 3(a+b)(b+c)(c+a)

Let (a+b) = x, (b+c) = y, (c+a) = z

Now,

=> (a+b)³+(b+c)³+(c+a)³ - 3(a+b)(b+c)(c+a)

=> x³+y³+z³ - 3xyz = (x+y+z)(x²+y²+z²-xy-yz-zx)

=>x³+y³+z³ - 3xyz = (a+b+b+c+c+a){(a+b)²+(b+c)²+(c+a)²-(a+b)(b+c) -(b+c)(c+a) -(c+a)(a+b)

=>x³+y³+z³ - 3xyz = (2a+2b+2c)(a²+b²+2ab+b²+c²+2bc+c²+a²+2ac -(ab+ac+bc+b²) -(bc+ab+ac+c²) -(ac+ab+bc+a²)

=> x³+y³+z³ - 3xyz = 2(a+b+c)(a²+b²+b²+c²+c²+a²+2ab+2bc+2ca-ab-bc-ac-b²-ac-bc-ab-c²-bc-ab-ac-a²)

=> x³+y³+z³ - 3xyz = 2(a+b+c)(a²+b²+c²-ab-bc-ca)

=> (a+b)³+(b+c)³+(c+a)³ - 3(a+b)(b+c)(c+a) = 2(a+b+c)(a²+b²+c²-ab-bc-ca)

here is your answer

hope it will help you