Question

(A/b)^x-1=(a/b)^2x-8 , find the value of x . for 9 standard

Answer 1

(a/b)^(x - 1) = (a/b)^(2x - 8) (eliminate a/b)
x - 1 = 2x - 8
-1 + 8 = 2x - x
x = 7

Answer 2

hope it helps u......