Question

(a/b)^x-1=(b/a)^2x-8

Answer 1

Answer: what is this

Step-by-step explanation:

Answer 2

Answer:

$( { \frac{a}{b} })^{x - 1} = ({ \frac{b}{a} })^{2x - 8} \\ = > (a {b}^{ - 1} ) ^{x - 1} = ( {ba}^{ - 1} ) ^{2x - 8} \\ = >$