Question

(-a) b2 - cd2 - 3b (-c)?, when a = 5, b = -7, c = 4, d = -3​

Answer 1

Answer:

-365

Step-by-step explanation:

=(-5)*(-7*-7)-[4*(-3*-3)]-3(-7)*(-4)

=(-5)*49-36+21(-4)

=(-245)-36-84

=(-365) Ans.

Answer 2

$(-a) b^2 - cd^2 - 3b (-c)=-365$

Step-by-step explanation:

Given : Expression $(-a) b^2 - cd^2 - 3b (-c)$

To find : The value of expression when a = 5, b = -7, c = 4, d = -3​ ?

Solution :

Expression $(-a) b^2 - cd^2 - 3b (-c)$

Substitute the value in the expression, a = 5, b = -7, c = 4, d = -3

$(-a) b^2 - cd^2 - 3b (-c)=(-5) (-7)^2 - (4)(-3)^2 - 3(-7) (-4)$

$(-a) b^2 - cd^2 - 3b (-c)=(-5) (49) - (4)(9) - 3(28)$

$(-a) b^2 - cd^2 - 3b (-c)=-245 -36- 84$

$(-a) b^2 - cd^2 - 3b (-c)=-365$

Therefore, $(-a) b^2 - cd^2 - 3b (-c)=-365$.

#Learn more

If (4/5)A = 3B = (2/3)C, then what is A : B : C?

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