A baby crawls 12 ft towards east 4feet towards south ans?
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Taking east as positive and west as negative.
from initial position, baby goes 12 feet east- (+12) feet
then towards the end the baby goes 9 feet west- (-9) feet
⇒Resultant displacement along x-axis- (12-9) = (+3) feet
The baby also travels 4 feet south and no movement north.
This forms a right angled triangle with base- 3 feet, perpendicular- 4 feet. And you want to find the hypotenuse.
H² = B² + P².
⇒H = √B²+ P²
⇒H = √3² + 4²
⇒H = √9 + 16
⇒H = √25
⇒H = +5 or -5
(But distance cannot be negative)
Therefore, the baby is 5 feet away from initial position.
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from initial position, baby goes 12 feet east- (+12) feet
then towards the end the baby goes 9 feet west- (-9) feet
⇒Resultant displacement along x-axis- (12-9) = (+3) feet
The baby also travels 4 feet south and no movement north.
This forms a right angled triangle with base- 3 feet, perpendicular- 4 feet. And you want to find the hypotenuse.
H² = B² + P².
⇒H = √B²+ P²
⇒H = √3² + 4²
⇒H = √9 + 16
⇒H = √25
⇒H = +5 or -5
(But distance cannot be negative)
Therefore, the baby is 5 feet away from initial position.
hope this will help you
please mark me as brainliest
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