A bag A bag contains pens numbered from 1 to 17. A pen is drawn and replaced.Then one more pen is drawn and replaced. what will be the probability that frist pen drawn is even and second one is odd ?
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0
Answer:
7by 13 for odd number and 8by13even number
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Step-by-step explanation:
1) If we drawn 1 pen then probability of it's even is 8/17.
2) Now we replace it
3) Now the total number of pen is again 17
4) The probability of second pens is odd is 9/17
5) The condition of first pen is even and second pen is odd is (8/17)*(9/17)
6 ) The answer is 72/289
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