A bag contain 18 balls out of which 'x'ball are red
1. If one ball is drawn at random from the bag ,what is the probablity that is not red
2. If 2 more red ball are put in the bag ,the probability of drawing a red ball will be 9÷8times the probability of drawing a red in the first case .find the value of 'x,
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a] Probability= x/18
b] total red balls: x+2, total number of balls= 18+2= 20
hence, x+2/ 20=9/8*x/18
x+2/20= x/16 ( 9 and 18 are divisible)
x+2 (16) = 20x
16x + 32= 20x
32= 4x
x= 8.
Hope it helps =D
b] total red balls: x+2, total number of balls= 18+2= 20
hence, x+2/ 20=9/8*x/18
x+2/20= x/16 ( 9 and 18 are divisible)
x+2 (16) = 20x
16x + 32= 20x
32= 4x
x= 8.
Hope it helps =D
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