Question

A bag contain 3 Red ball 4 blue ball,
and 5 Green ball one ball is drawn
at random. find the probability,
a)Red
(B Not red
(c) Not Green​

Answer 1

Answer:

TOTAL BALLS = 12

P(R) = 3/12 = 1/4

P(NOT R) = 1 - P(R)

= 1 - 1/4 = 3/4

P( NOT GREEN) = 1 - P(G)

P(G) = 5/12

Therefore,

P( NOT G) = 1 - 5/12

= 7/12

Answer 2

Answer:

3 red Balls

4 blue balls

5 green balls

Total balls:-3+4+5

Todal Balls:-12

Probability of getting Red Balls:-12/3=4

Probability of getting blue balls:-12/4=3

Probability of getting green balls:-12/5=2.4

a)Red=4

b)Not red=5.4

c)Not green=7