A bag contain 3 red ball and 4 white balls. Two balls are drawn one after the other without replacement at after the other without replacement at random from the bag. If the second ball drawn is given to be white .What is the probability that first balls drawn is also white.
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Answer:
Hello , here is the answer to your question:
sample space = {r,r,r,w,w,w,w}
n(s)= 7
probability of drawing a white ball in the first attempt randomly:
a= {w,w,w,w}
n(a)=4
probability of the event = n(a) / n(s)
= 4/7
Good luck
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