Question

A bag contain 3 red swets​

Answer 1

Answer:

Answer: \dfrac{3}{28}

28

3

.

Step-by-step explanation:

Given : A bag contains 3 red and 5 green sweets. Tim takes a sweet at random and eats it.

Total sweets were in bag = 5+3=8

Number of ways to select 2 red sweets = 3\times2=63×2=6

Number of ways to select any two sweets = 8\times7=568×7=56

Now, the probability that Tim takes 2 red sweets is given by :-

\begin{gathered}=\dfrac{\text{Number of ways to take red sweets}}{\text{Number of ways to select any two sweets}}\\\\=\dfrac{6}{56}=\dfrac{3}{28}\end{gathered}

=

Number of ways to select any two sweets

Number of ways to take red sweets

=

56

6

=

28

3

Hence, the probability that Tim takes 2 red sweets is \dfrac{3}{28}

28

3

.