A bag contain 4red 3black and 2white balls.If three balls are selected random the probability of selecting atleast one white ball
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Hey mate ☺️
The bag contains 2 White, 3 Black and 4 Red balls.
So, total 9 balls are there in the bag; among them 2 are Black and 7 are non-Black balls.
Three balls can randomly be drawn in (9C3) = 84 ways.
1 white and 2 non-Black balls can be drawn in (2C1)*(7C2) = 42 ways.
1 non-white and 2 white balls can be drawn in (7C1)*(2C2) = 7 ways.
3 non-white can be drawn in (3C3) = 1 way.
So, three balls drawn in (42 + 7 + 1) = 50 ways will have at least one white ball among the drawn ones.
So, the probability of getting at least one white ball among the three drawn =
(50 / 84)Black = (25/42).
I hope it helps you ☺️✌️✌️
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