Question

A bag contain 5 white , 7 red,5 black and 4 green balls. If a ball is drawn at random from the bag. What is the probability that the ball is not black​

Answer 1

Answer:

Total no. of balls in a bag= 5+7+5+4= 21

No. of not black balls= 5+7+4=16

Therefore the probability of not getting a Black ball =16/21

Answer 2

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$\huge{\orange{\boxed{\fcolorbox{lime}{black}{\red{QUESTION}}}}}$

☘️ A bag contain 5 white , 7 red,5 black and 4 green balls. If a ball is drawn at random from the bag. What is the probability that the ball is not black .

$\huge{\orange{\boxed{\fcolorbox{lime}{indigo}{\color{aqua}ANSWER}}}}$

$\Large\bf{\color{cyan}GiVeN,}$

• A bag contain 5 white, 7 red, 5 black and 4 green balls.

$\longmapsto\:\:\rm{Total\:no.\:of\:balls\:=\:5\:+\:7\:+\:5\:+\:4\:}$

$\longmapsto\:\:\bf{Total\:no.\:of\:balls\:=\:21\:}$

$\red\checkmark\:\:\bf{Total\:no.\:of\:black\:ball\:=\:5\:}$

$\green\checkmark\:\:\bf{Total\:no.\:of\:nonblack\:ball\:=\:21\:-\:5\:=\:16}$

$\Large\bf{\color{pink}We\: know\:that,}$

$\red\bigstar\:\:\bf\purple{Probability\:=\:\dfrac{No.\:of\: favourable\: outcomes}{Total\:no.\:of\: outcomes}\:}$

$\Large\bf{\color{indigo}So,}$

$\longmapsto\:\:\bf\orange{P\:(not\: black\:ball)\:=\:\dfrac{16}{21}\:}$