English, asked by chitramanval2706, 4 months ago

A bag contain 8 white and 2 green balls drawn from the bag find the probability that is a) green ball b) not a white ball​

Answers

Answered by Sanumarzi21
0

A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag.

Then total number of balls in bag =6+8+5+2+1=22

Total number of out come =22

(i)The event is getting a White ball=number of white ball in bag=8

Then probability=

22

8

=

11

4

(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)

The probability=

22

9

(iii)The event getting the Not green is total number of ball other then green ball=6+8+2+1=17

The probability=

22

17

(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11

The probability=

22

11

=

2

1

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Answered by 2601ar
0

Answer:

total no. of balls=10

p(getting a green ball)=2/10

=1/5

p( not getting a white ball)=2/10

=1/5

Explanation:

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