A bag contain 8 white and 2 green balls drawn from the bag find the probability that is a) green ball b) not a white ball
Answers
A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag.
Then total number of balls in bag =6+8+5+2+1=22
Total number of out come =22
(i)The event is getting a White ball=number of white ball in bag=8
Then probability=
22
8
=
11
4
(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)
The probability=
22
9
(iii)The event getting the Not green is total number of ball other then green ball=6+8+2+1=17
The probability=
22
17
(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11
The probability=
22
11
=
2
1
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Answer:
total no. of balls=10
p(getting a green ball)=2/10
=1/5
p( not getting a white ball)=2/10
=1/5
Explanation:
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