The tuning circuit of a radio receiver has a
resistance of 50 12, an inductance of 10 mH and a
variable capacitance C. A 1 MHz radio wave
produces a potential difference of 0.1 mV. The
value of capacitance to produce the resonance
will be
(a) 25pF
(6) 5.0 pF
(c) 25pF
(d) 50 pF
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Answer of your question is 2.5 pF
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