Question

A bag contain of 8apple and 6orange Four fruit are drawn out one by one and not replaced what is the probablity that they are alternatively of different fruits?​

Answer 1

Answer:

There are total (8 + 6) = 14 fruits.

Any four fruits can be drawn in (14P4) = 24024 ways. Be mindful, unlike common thinking here we have to apply permutation; because every single draw has the potential of giving different outcomes.

Now, we are to look for the cases of selections of ‘apple - orange - apple - orange’ and ‘orange - apple - orange - apple' only. They can happen in {(8*6*7*5) + (6*8*5*7)} = 3360 ways.

Therefore, the probability = (3360 / 24024) = (140 / 1001) = (20 / 143) = 0.13986.