Question

A bag contains 10 fruits out of which 3 fruits are bad.Two fruits are are taken out together at random.If one fruit is good then what is the probability of getting other fruit also a good one?

Answer 1

Answer:

10 fruits

3 are bad so remaining 7 are good

one good fruit is already picked.

so remaining good fruits =6

proabbility of getting one good fruit is selecting one among all remaining fruits

remaining fruits = 6good+ 3 bad

so probability is 6/9

= 2/3

Answer 2

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Good fruits = 7

Bad fruits = 3

If 1st fruit is good then probability of 2nd fruit to be good is

$\frac{7-1}{10-1}$

= $\frac{6}{9}$

= $\frac{2}{3}$