A bag contains 6 red balls and 7 white balls. Another bag contains 5 red balls and 3 white balls.One ball is selected from each. Find the probability that one ball is red and one is white?
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Answer:
For the first bag (red balls)=6/13
For the first bag (white balls)=7/13
This method we will be applying it for the 2nd bag also
Step-by-step explanation:
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Answer:
probabilty of first bag
red ball = favourable outcome upon
total outcome
= 6 upon 13
white ball = favourable outcome upon
total outcome
= 7 upon 13
probability of second bag
red ball = favourable outcome upon
total outcome
= 5 upon 8
white ball = favourable outcome upon
total outcome
= 3 upon 8
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