Question

A bag contains 10 mangoes out of which 4 are taken out together . if one of them is found to be good, the probability that other is also good is

Answer 1

Answer:

According to the problem,

A bag contains 6 good mangos and 4 rotten mangos

It is a problem of conditional probability

The probability of taking a good mango from the total mangos is

$P_1 = \frac{6}{10}$

The probability of taking another good mango from the total mangos is

$P_2 = \frac{5}{9}$

Already we had taken 1 good mango therefore we left with 5 good mangos out of 9 mangos

Therefore, Total probability $P = P_1 \times P_2 = \frac{1}{3}$