Question

A bag contains 10-paisa, 20-paisa and 25-paisa coins in the ratio 7:4:3. if the total value is rs. 90, thenumber of 25-paisa coins in the bag is:

Answer 1

let 10 paise , 20 paise , 25 paise be 7x,4x,3x respectively
10 paise = 10/100 rs = 1/10 rs
20paise =20/100 rs = 1/5 rs
25 paise = 25/100 rs = 1/4 rs
therefore
total amount in 10 paise = 1/10×7x = 7x/10
total amount in 20 paise = 1/5×4x = 4x/5
total amount in 25 paise = 1/4×3x = 3x/4
so , according to question
7x/10 + 4x/5 + 3x/4 = 90
(14x+16x+15x)/20 = 90
45x/20 = 90
45x =1800
x=1800/45 = 40
number of 25 paise coins = 3x = 3×40 = 120
hope this helps

Answer 2

Answer:

120

Step-by-step explanation:

let 10 paise , 20 paise , 25 paise be 7x,4x,3x respectively

10 paise = 10/100 rs = 1/10 rs

20paise =20/100 rs = 1/5 rs

25 paise = 25/100 rs = 1/4 rs

therefore

total amount in 10 paise = 1/10×7x = 7x/10

total amount in 20 paise = 1/5×4x = 4x/5

total amount in 25 paise = 1/4×3x = 3x/4

so , according to question

7x/10 + 4x/5 + 3x/4 = 90

(14x+16x+15x)/20 = 90

45x/20 = 90

45x =1800

x=1800/45 = 40

number of 25 paise coins = 3x = 3×40 = 120

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