Math, asked by pgracevolau5869, 1 year ago

A bag contains 5 green coins and 4 red coins and other contains 3 green coins and 2 red coins..what it propability of getting no green coins

Answers

Answered by Aze
3
=14-(5+3)/14
=6/14
=3/7
Answered by lovingheart
0

Answer:

The probability of getting no green coins is 2/5.

Step-by-step explanation:

BAG1:

Step 1:

Total number of green coins=5

Total number of red coins=   4

Total no.of coins              =   9

Probability of no green coins=?

Step 2:

Probability of green coins=number of green coins/total no.of coins

        =5/9

Step 3:

Probability of no green coins in bag1=1-P(n)

    =1-5/9

    =4/9

BAG 2:

Step 4:

Total number of green coins=3

Total number of red coins=   2

Total no.of coins              =   5

Probability of no green coins=?

Step 5:

Probability of green coins = number of green coins/total no. of coins

        =3/5

Step 6:

Probability of  no green coins in bag2=1-P(n)

    =1-3/5

    =2/5

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