A bag contains 5 green coins and 4 red coins and other contains 3 green coins and 2 red coins..what it propability of getting no green coins
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Answered by
3
=14-(5+3)/14
=6/14
=3/7
=6/14
=3/7
Answered by
0
Answer:
The probability of getting no green coins is 2/5.
Step-by-step explanation:
BAG1:
Step 1:
Total number of green coins=5
Total number of red coins= 4
Total no.of coins = 9
Probability of no green coins=?
Step 2:
Probability of green coins=number of green coins/total no.of coins
=5/9
Step 3:
Probability of no green coins in bag1=1-P(n)
=1-5/9
=4/9
BAG 2:
Step 4:
Total number of green coins=3
Total number of red coins= 2
Total no.of coins = 5
Probability of no green coins=?
Step 5:
Probability of green coins = number of green coins/total no. of coins
=3/5
Step 6:
Probability of no green coins in bag2=1-P(n)
=1-3/5
=2/5
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