A bag contains 12 balls out of which x are black.
(i) If a ball is drawn at random, what is the probability that it will be a black ball?
(ii) If 6 more black balls are put in the bag, the probability of drawing a black ball will be
double than that of (i). Find the value of x
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Step-by-step explanation:
ANSWER ::
i) Total number of possible outcomes = 12
Let A be the event that the ball will be a black ball
Then the number of possible outcomes = x
So P(A) = x /12
ii) Total number of possible outcomes = 18
Let B be the event that the ball will be a black ball
be the event that the ball will be a black ball Then the number of possible outcomes = x + 6
So P(B) = x+6 / 18
Now
x+6 / 18 = 2x /12
x+6 / 18 = x /6
x + 6 = 3x
2x = 6
x = 3
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