A bag contains 12 red, 9 green, 8 blue, and 5 yellow balls. A ball is thrown from the bag at random. Find the probability of getting (i) a green ball, (ii) a yellow ball, (iii) a white ball
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Answered by
10
1....9/32
2.....5/32
3....0/32
2.....5/32
3....0/32
jiteshpareek:
9/34;5/34;0
thnx
Answered by
29
total ball= 12+9+8+5=34
means sample space= 34
1. p(green)= 9/34
2.p(yellow)=5/34
3.p(white)= 0 as no white balls are there
means sample space= 34
1. p(green)= 9/34
2.p(yellow)=5/34
3.p(white)= 0 as no white balls are there
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