A bag contains 13 black and 16 green balls. A boy draws 2 balls in succession from the bag without replacement. Calculate the probability that the first ball drawn is black and the second one drawn is green.
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1st ball
1/29
2nd ball
1/29
1/29
2nd ball
1/29
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probability of first ball= no. of fav. outcomes ÷total no. of outcomes
So, P (E) = 13÷(13+16)
=13÷29
now similarly,
probability of second ball=
no. of fav. outcomes ÷total no. of outcomes
so, P (E)= 16÷29
HOPE IT WILL HELP YOU
So, P (E) = 13÷(13+16)
=13÷29
now similarly,
probability of second ball=
no. of fav. outcomes ÷total no. of outcomes
so, P (E)= 16÷29
HOPE IT WILL HELP YOU
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