Question

A bag contains 2 red marbles, 2 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

Answer 1

Answer:

Probability(of getting red marble) = Number of favourable events/ Total events

P(of getting red marble)= 2/8= 1/4

Probability (of getting green marble) = 2/8 = 1/4

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?