A bag contains 20 balls marked 1 to 20 .One ball is drawn at random from the bag.What is the probability that the ball drawn is marked with a number which is a multiple of 5 or 7.
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P=no of required outcome/total no of possible outcome
=6/20=3/10
=6/20=3/10
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0
P(E) =4/20=1/5 (for 5)
P(E) =2/20=1/10(for 7)
4/20+2/20=6/20
=3/10
P(E) =2/20=1/10(for 7)
4/20+2/20=6/20
=3/10
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