Question

A bag contains 3 blue, 2 green and 5 red balis. If four balls are picked at random, what is the probability that two are green and two are blue?​

Answer 1

Answer:

Number of blue balls = 3

Number of green balls = 2

Numbers of red balls = 5

Total balls in the bag = 3 + 2 + 5 = 10

Total possible outcomes = Selection of 4 balls out of 10 balls

Step-by-step explanation:

• =10 C_4 = 10/4x(-10/4)

=10×9×8×7/1×2×3×4

= 210

Favorable outcomes = (selection of 2 green balls out of 2 balls) × (selection of 2 balls out of 3 blue balls)

=2C2×3C2=1×3=3

∴ Required probability

=Favorable Outcomes Total possible outcomes

=3210=170