Question

A bag contains 3 red and 5 green sweets Tim takes a sweet at random and eats it he then takes another sweet find the probability that Tim takes 2 red sweets

Answer 1

Given:

A bag contains 3 red and 5 green sweets Tim takes a sweet at random and eats it he then takes another sweet  

To find:

Find the probability that Tim takes 2 red sweets

Solution:

From given, we have,

A bag contains 3 red and 5 green sweets

3 + 5 = 8  

Therefore, there are 8 sweets in total

Tim takes a sweet at random and eats it  

As there are 3 red sweets out of 8, so the probability is given by,

P(R1) = 3/8

The sweets left after picking the first sweet is 7 sweets with 2 red ones.

As there are 2 red sweets out of 7, so the probability is given by,

P(R2) = 2/7

Thus, the probability of both is given by,

P(R) = P(R1) × P (R2) = 3/8 × 2/7 = 3/28

Therefore, the probability that Tim takes 2 red sweets is P(R) = 3/28