a bag contains 3 red and some blue balls.if the probability of drawing a blue ball is four times that of drawing a red ball, find the number of blue balls.
pls solve this it is urgent...........
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LET THE NO. OF BLUE BALLS BE X
NO. OF RED BALLS = 3
TOTAL NO. OF BALLS = NO. OF BLUE BALLS + NO. OF RED BALLS
= X + 3
PROBABILITY OF GETTING BLUE BALL = X / X + 3
PROBABILITY OF GETTING RED BALL = 3/ X +3
ACCORDING TO THE QUESTION,
X / X + 3= 4 * 3 / X + 3
CANCELLING X+3 FROM BOTH TERMS AS THEY ARE COMMON
X = 12
SO, THERE ARE 12 BLUE BALLS IN THE BAG.
NO. OF RED BALLS = 3
TOTAL NO. OF BALLS = NO. OF BLUE BALLS + NO. OF RED BALLS
= X + 3
PROBABILITY OF GETTING BLUE BALL = X / X + 3
PROBABILITY OF GETTING RED BALL = 3/ X +3
ACCORDING TO THE QUESTION,
X / X + 3= 4 * 3 / X + 3
CANCELLING X+3 FROM BOTH TERMS AS THEY ARE COMMON
X = 12
SO, THERE ARE 12 BLUE BALLS IN THE BAG.
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