Question

A bag contains 3 red balls and 4 white balls. Two balls are drawn one after the other without replacement at random from the bag. If the second ball drawn is given to be white, what is the probability that the first ball drawn is also white?

plz help... ​

Answer 1

Answer:

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

$\huge\mathtt{{\colorbox{silver}{ANSWER~~~↴}}}$

sample space = {r,r,r,w,w,w,w}

n(s)= 7

probability of drawing a white ball in the first attempt randomly:

a= {w,w,w,w}

n(a)=4

probability of the event = n(a) / n(s)

⇒ 4/7

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

Answer 2

Answer:

So here is Your answer.

Hope it will help U dear.