a bag contains 3 red balls and 5 black balls. A ball is selected at random from the bag . what is the probability that the ball selected is (1) red ? (2) not red ?
Answers
Answered by
4
Answer:
1.3/8
2.5/8
Step-by-step explanation:
no. of sample space =5+3=8
P(e)of red =no. of event/no. of sample space
= 3/8
p(e)not red =5/8
Answered by
3
Answer:
(1) 3/8
(2) 5/8
Step-by-step explanation:
total balls = (3+5) = 8
n(S) will be = 8c1 = 8
(1) we have to drawn 1 red ball from 3 red balls . let the incident be A
hence, n(A) = 3c1 = 3
hence the probability of getting red ball = n(A) /n(S) = 3/8
(2) we have to drawn a ball which is not red in colour
= the black balls of the bag
hence, n(B) = 5c1 = 5
hence the probability of not getting red ball = n(B)/n(S) = 5/8
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