find value of k for which one root of the quadratic equation kx square -14x+8=0 is 2
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hey mate here is your answer ✌♥✌
let p(X)=kx²-14x+8
now as 2 is a root
p(2)=k(2)²-14(2)+8=0
4k=28-8
k=20/4
k=5
hope it will help you
mark me brainliest ✌✌✌✌
let p(X)=kx²-14x+8
now as 2 is a root
p(2)=k(2)²-14(2)+8=0
4k=28-8
k=20/4
k=5
hope it will help you
mark me brainliest ✌✌✌✌
khushboo4864:
nd u
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